Python: Get number of years that have passed from date string

Question

Given that I start with a string, like '3/6/2011' which is month/day/year, and the current day is 3/13/2011 (7 days later), how can I find the number of years that have passed since that time (7/365 = 0.0191780821917808) in Python?

Note that I want to be able to handle any input date. Not any format though, you can assume the format above.

score 11 · Accepted Answer · edited May 23 '17 at 12:19

11

You can get the timedelta by subtracting two datetimes, which gives you a lot of cool ways to operate on the time difference.

>>> import datetime
>>> before = datetime.datetime.strptime('3/6/2011','%m/%d/%Y')
>>> now = datetime.datetime.now()
>>> type(now-before)
<type 'datetime.timedelta'>
>>> (now-before).days
7
>>> float((now-before).days)/365
0.019178082191780823

EDIT: Wow, who would've thought there was so much depth to this simple question. Take a look at the answer with the most votes on this question. Dealing with leap years is a "hard" problem. (Credit to @kriegar)

edited May 23 '17 at 12:19

Community

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answered Mar 14 '11 at 03:14

Chris W.

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I'd then divide (now-before).days by 365 to get the fractional year. – John Percival Hackworth Mar 14 '11 at 03:15
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aren't leap years are a problem with this solution? – dting Mar 14 '11 at 03:25
I'm already going to have some margin of error for my application, so leap years probably aren't all that much of a worry, since the inaccuracy from this is < 1%. Thanks for the solution – Muhd Mar 14 '11 at 03:53

score 1 · Answer 2 · answered Mar 14 '11 at 03:15

1

>>> import datetime
>>> datestring = "3/6/2011"
>>> (datetime.date.today() - datetime.datetime.strptime(datestring, "%m/%d/%Y").date()).days / 365.0
0.019178082191780823

answered Mar 14 '11 at 03:15

Wooble

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Python: Get number of years that have passed from date string

2 Answers2