Error java.lang.ArrayIndexOutOfBoundsException

Question

I looked over on stackoverflow but I still can't figure what's wrong with the code. PS: I am a beginner /****************************************************************/

class Main 
{
  public static void main(String[] args) 
  {
    int SIZE = 10;
    int[] sortedArray = new int[SIZE];
    int[] intArray = new int[]{ 5,2,10,4,1,6,99,8,9,1 };
    int x=0;
    int y=0;
    // Random big nunbver to ensure no number in array is bigger
    int biggestNumberFound = 10000000;
    int maxValue=0;
    for ( x = 0; x <= SIZE; x++) 
      for ( y = 0; y <= SIZE; y++)
        maxValue = 0;
        if (intArray[y] > maxValue && intArray[y] < biggestNumberFound)
          maxValue = intArray[y];
      sortedArray[x] = maxValue;
      biggestNumberFound = maxValue;
    System.out.println(sortedArray);
  }

}

/***********************************************/

The error: Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 11 at Main.main(Main.java:17) exit status 1

This means that in line 17 of Main.java you access an array element with index 11 that does not exist. — Henry, Oct 23 '18 at 09:40
arrays are zero based, therefore the valid range in this case is 0 to 9. The for loop iterates from 0 to 10, hence the error — Samuel Kok, Oct 23 '18 at 09:41
Also, you have problems with scopes, add curly brackets after each for loop and specify area which this loop should affect — Oleksandr Riznyk, Oct 23 '18 at 09:45

score 0 · Answer 1 · answered Oct 23 '18 at 09:41

0

for ( x = 0; x <= SIZE; x++)

x should less than SIZE instead of <= since array begin with index 0 and end with (size-1)

answered Oct 23 '18 at 09:41

Dang Nguyen

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I've tried with x – padurean04 Oct 23 '18 at 09:42
@CatalinPadurean there is exactly the same problem with `y` as well. – Henry Oct 23 '18 at 09:45
Done for y as well, forgot to mention – padurean04 Oct 23 '18 at 09:46
@Catalin Padurean and please add some `{` before and `}` after for block – Dang Nguyen Oct 23 '18 at 09:46
`for (x = 0; x maxValue && intArray[y] < biggestNumberFound) maxValue = intArray[y]; sortedArray[x] = maxValue; biggestNumberFound = maxValue; } }` – Dang Nguyen Oct 23 '18 at 09:47
Thank you so much guys. – padurean04 Oct 23 '18 at 09:51
@CatalinPadurean - just for clarification, when you didn't add brackets, your for loop used to execute before the executing the condition, **if (intArray[y] > maxValue && intArray[y] < biggestNumberFound)** and the value of y being 10, you were getting ArrayIndexOutOfBoundsException – Pranali Rasal Oct 23 '18 at 09:55
Yes, it makes sense. I got that after I put the brackets. Thanks for the explanation :) – padurean04 Oct 24 '18 at 08:29

Error java.lang.ArrayIndexOutOfBoundsException

1 Answers1