if variable == 'String' : doSomething()?

Question

I compare each element of the list ['a','c'] in an if-statement control flow with a string like this:

charlist = ['a','b']

for el in charlist:
    if el is'a' or 'A':
        print('a is done')
    if el is 'b' or 'B':
        print('b is done')
    if el is 'c' or 'C':
        print('why c?')

Output is:
a is done
b is done
why c?

why does this execute the "if el is 'c' or 'C':" statement?
I think only the first two are executed?

But this solution worked for me

for el in charlist:
    if el == 'a' or el == 'A':
       print('a is done')
    if el == 'b' or el == 'B':
       print('b is done')
    if el == 'c' or el == 'C':
       print('c is done')

@dfundako True enough, I've already removed my comment. The pattern-matcher in my visual cortex mistook `if el` for `elif`. — Eli Korvigo, Oct 23 '18 at 19:31
You might also take a look at this [post](https://stackoverflow.com/questions/52851057/not-sure-why-my-if-and-else-statements-are-not-working-in-python#comment92617822_52851057), because it is an exact duplicate of your question and the comments show better solutions than the one you've picked. — Eli Korvigo, Oct 23 '18 at 20:58

score -1 · Answer 1 · answered Oct 23 '18 at 19:28

-1

Try doing it this way for clarity:

charlist = ['a','b']

for el in charlist:
  if el =='a' or el =='A':
     print('a is done')
  if el == 'b' or el =='B':
     print('b is done')
  if el == 'c' or el == 'C':
      print('why c?')

answered Oct 23 '18 at 19:28

clearshot66

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if variable == 'String' : doSomething()?

1 Answers1