Fix EOF error when taking list as input and checking if sorted?

Asked Oct 25 '18 at 19:14

Active Oct 25 '18 at 19:45

Viewed 93 times

Here is my code:

lstInput = input('Type here: ')
lst = list(lstInput)
def is_sorted(lst):
    if len(lst) == 1:
        return True
    else:
        for x in range(len(lst)):
            if lst[x] > lst[x+1]:
                return False
    return True
is_sorted(lst)

When I try to run it in zybooks, my class textbook, I get an EOF error for lstinput = input("Type here: "). I do not get an error in IDLE. Please help. Thanks

edited Oct 25 '18 at 19:45

asked Oct 25 '18 at 19:14

Shayna Prinz

This question is probably too localized, but can you share a link to that notebook? – DeepSpace Oct 25 '18 at 19:17
By the way, `lst` is going to be a string and not a list as you expect it to be. – DeepSpace Oct 25 '18 at 19:20
Related: [Get a list of numbers as input from the user](https://stackoverflow.com/questions/4663306/get-a-list-of-numbers-as-input-from-the-user) – DeepSpace Oct 25 '18 at 19:21

Fix EOF error when taking list as input and checking if sorted?

0 Answers0