Suppose I have a three dimensional array, which I'll call A, where the first dimensional is equal to N. How do I find B, which is equivalent to:
np.concatenate((A[0],A[1],A[2],...,A[N-1]),axis=1)
As an example, suppose I have:
A = np.array([[[1,2,3,4],[5,6,7,8]],[[9,10,11,12],[13,14,15,16]],[[17,18,19,20],[21,22,23,24]]])
print(A)
[[[ 1 2 3 4]
[ 5 6 7 8]]
[[ 9 10 11 12]
[13 14 15 16]]
[[17 18 19 20]
[21 22 23 24]]]
How do I (in a single line) return B, which will be equal to:
print(B)
[[ 1 2 3 4 9 10 11 12 17 18 19 20]
[ 5 6 7 8 13 14 15 16 21 22 23 24]]
I've tried reshaping, but this doesn't return the required order of the elements. Thanks.
