How can this code printf() properly although I allocated less memory than it requires.
char* String;
char String2[] = "testing";
String =(char*) malloc(4 * sizeof(char));
strcpy(String,String2);
printf("NAME : %s",String);
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keser
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1Undefined behavior is undefined. Welcome to C. I'll try to find one the 100 duplicate questions. – melpomene Oct 27 '18 at 12:06
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`strcpy(String,String2);` --> What did you think should happen? – chux - Reinstate Monica Oct 27 '18 at 18:31
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@chux segmentation fault or sth like that? – keser Oct 28 '18 at 11:18
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1aomerk, C does is not specified to catch coding mistakes. That is one of the reasons for its execution speed. If you want to code in a way that always catches such errors as overwriting a buffer, consider anther language and accept its performance. – chux - Reinstate Monica Oct 28 '18 at 14:14