How to input n number of elements into an array using scanf()?

Question

Is there a way to input n of inputs into an array, where n is not fixed, using scanf()?

scanf("%d %d %d %d ... n number of inputs", &array);

The problem is that a user enters the size of an array, and the input format is that the inputs are stored using scanf in a single line, so it is of the form

12 24 36 34 65 24 54 ... upto n inputs

So that the first %d is stored in array[0], the second into array[1], third into array[2], and all the way upto array[n-1].

It is easy to make a for loop for this, but I want to do it in a single line.

Why do you want to do it in a single line when you already know of an easy way to do it? — Chris Turner, Oct 29 '18 at 16:54
"I want to do it in a single line." Apart from writing your own function to do it, you can't do it in a single line. But then again it wouldn't be a single line if you write a function. — Sergey Kalinichenko, Oct 29 '18 at 16:55
Read this https://stackoverflow.com/questions/11695237/creating-va-list-dynamically-in-gcc-can-it-be-done and go for vfscanf() ... :-) — alk, Oct 29 '18 at 17:18

suvojit_007 · Answer 1 · 2018-10-29T20:40:12.947

1

Not one-liner but still short

while(i < n && scanf("%d", &array[i]) == 1)
    i++;

You should always check the return value of scanf function.
Don't forget to initialize i with 0

edited Oct 29 '18 at 20:40

answered Oct 29 '18 at 17:02

suvojit_007

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Don't break the line before i++ - and a one-liner it is. – DYZ Oct 29 '18 at 20:47

How to input n number of elements into an array using scanf()?

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