I am attempting to use the spp.est function of the package called "fossil" in RStudio. I have created a matrix called "akimiskibb" of abundance data with species as the columns and sites as the rows. When I try to use the function spp.est, I type this:
spp.est(akimiskibb, rand = 10, abund = TRUE, counter = FALSE, max.est = 'all')
The problem comes in because my abundance data has a lot of zeroes, so I get this error message:
Error in if (max(x) == 1) warning("cannot use incidence data for abundance-based analyses. If the data is incidence based, please run this function again with the option of 'abund=FALSE'") : missing value where TRUE/FALSE needed
This function has worked in the past with matrices with a lot of zeroes (which are also abundance data, not presence/absence). I don't know what I am doing wrong.
Has anyone experienced something similar and found a way around this?
Thank you,
Kayla
Data: matrix format:
*sp1 sp2 sp3 sp4 sp5 sp6 sp7 sp8 sp9 sp10 sp11 sp12 sp13 sp14 sp15 sp16 sp17
sample1 0 0 0 0 0 0 0 1 0 0 0 0 0 0 1
0 0
sample 2 0 0 0 1 0 0 1 25 7 0 18 12 0 0 0
1 1
sample3 0 0 0 0 0 0 0 3 0 0 3 1 0 0 0
5 4
sp18 sp19 sp20 sp21 sp22 sp23 sp24 sp25 sp26 sp27 sp28 sp29 sp30 sp31
sp32
sample1 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0
sample 2 1 0 1 0 0 0 0 0 0 0 0 3 2
0 3
sample3 0 0 1 0 0 11 0 0 0 0 0 0 0
0 1
sp33 sp34 sp35 sp36 sp37 sp38 sp39 sp40 sp41 sp42 sp43 X
sample1 0 0 0 0 0 0 0 0 0 0 0 NA
sample 2 0 0 3 2 1 0 0 1 8 0 0 NA
sample3 0 0 0 0 0 0 0 0 0 0 0 NA*
dput:
*structure(list(sp1 = c(0L, 0L, 0L), sp2 = c(0L, 0L, 0L), sp3 = c(0L,
0L, 0L), sp4 = c(0L, 1L, 0L), sp5 = c(0L, 0L, 0L), sp6 = c(0L,
0L, 0L), sp7 = c(0L, 1L, 0L), sp8 = c(1L, 25L, 3L), sp9 = c(0L,
7L, 0L), sp10 = c(0L, 0L, 0L), sp11 = c(0L, 18L, 3L), sp12 = c(0L,
12L, 1L), sp13 = c(0L, 0L, 0L), sp14 = c(0L, 0L, 0L), sp15 = c(1L,
0L, 0L), sp16 = c(0L, 1L, 5L), sp17 = c(0L, 1L, 4L), sp18 = c(0L,
1L, 0L), sp19 = c(0L, 0L, 0L), sp20 = c(0L, 1L, 1L), sp21 = c(0L,
0L, 0L), sp22 = c(0L, 0L, 0L), sp23 = c(0L, 0L, 11L), sp24 = c(0L,
0L, 0L), sp25 = c(0L, 0L, 0L), sp26 = c(0L, 0L, 0L), sp27 = c(0L,
0L, 0L), sp28 = c(0L, 0L, 0L), sp29 = c(0L, 3L, 0L), sp30 = c(0L,
2L, 0L), sp31 = c(0L, 0L, 0L), sp32 = c(0L, 3L, 1L), sp33 = c(0L,
0L, 0L), sp34 = c(0L, 0L, 0L), sp35 = c(0L, 3L, 0L), sp36 = c(0L,
2L, 0L), sp37 = c(0L, 1L, 0L), sp38 = c(0L, 0L, 0L), sp39 = c(0L,
0L, 0L), sp40 = c(0L, 1L, 0L), sp41 = c(0L, 8L, 0L), sp42 = c(0L,
0L, 0L), sp43 = c(0L, 0L, 0L), X = c(NA, NA, NA)), .Names = c("sp1",
"sp2", "sp3", "sp4", "sp5", "sp6", "sp7", "sp8", "sp9", "sp10",
"sp11", "sp12", "sp13", "sp14", "sp15", "sp16", "sp17", "sp18",
"sp19", "sp20", "sp21", "sp22", "sp23", "sp24", "sp25", "sp26",
"sp27", "sp28", "sp29", "sp30", "sp31", "sp32", "sp33", "sp34",
"sp35", "sp36", "sp37", "sp38", "sp39", "sp40", "sp41", "sp42",
"sp43", "X"), class = "data.frame", row.names = c("sample1",
"sample 2", "sample3"))*
packages used:
fossil (made in R version 3.4.4)
Version of R: R x64 3.4.1