Python create custom magic methods

Question

In python, if I wanted to create an object that did something when passed to a specific function, how could I do that? For example:

import logging
class  TestObject:
    def __logging__(self):
        # It would check the calling function here and return something 
        # if it was a log function call from a logging class log function call
        return 'Some text'

Check out this post: https://stackoverflow.com/questions/2654113/how-to-get-the-callers-method-name-in-the-called-method — charley, Oct 31 '18 at 14:08

score 8 · Answer 1 · edited Jan 01 '21 at 10:46

Basic Idea

In python all the default, or inbuild dunder methods are called by specific function. For example, the __next__ is called by next(), __len__ is called by len(), ... etc. So when we make a custom dunder method I suggest you to make a function that can call the dunder method.

The code

# lets first make a function that will call a the logging method
# the function accepts an argument which is a class that is assumed to have a
# __logging__ method.


def logging(cls):
    return cls.__logging__()

class Cls:
    def __logging__(self):
        return "logging called"

# you can use this method by this code

cls = Cls()
print(logging(cls))  # output => logging called

# or if you don't have a function to call the dunder method
# you can use this

cls = Cls()
print(cls.__logging__())  # output => logging called

Please include an explanation of your code. Code-only answers are generally frowned upon on SO. — mypetlion, Feb 06 '19 at 18:47

Python create custom magic methods

1 Answers1

Basic Idea

The code