Ask for correct input untill it is given in python

Question

I have a code that is asking a user if they wanna play a game they either press Y or N. If they press Y it asks them to choose a number between 1 and 10 if they press N it says oh okay.

But I want it to ask again if the user input is not y or n. and if they dont press y or n it will ask again and again and again untill they press y or n.

#!/usr/bin/env python3

import random

number = random.randint(1, 10)
tries = 0
win = False # setting a win flag to false


name = input("Hello, What is your username?")

print("Hello" + name + "." )


question = input("Would you like to play a game? [Y/N] ")
if question.lower() == "n": #in case of capital letters is entered
    print("oh..okay")
    exit()
if question.lower() == "y":
    print("I'm thinking of a number between 1 & 10")


while not win:  # while the win is not true, run the while loop. We set win to false at the start therefore this will always run
    guess = int(input("Have a guess: "))
    tries = tries + 1
    if guess == number:
        win = True    # set win to true when the user guesses correctly.
    elif guess < number:
        print("Guess Higher")
    elif guess > number:
        print("Guess Lower")
# if win is true then output message
print("Congrats, you guessed correctly. The number was indeed {}".format(number))
print("it had taken you {} tries".format(tries))

score 0 · Answer 1 · answered Nov 01 '18 at 00:15

Add a while loop to make sure they choose one of them:

[..]
question = ''
while question.lower() not in ['n', 'y']:
    question = input("Would you like to play a game? [Y/N] ")

if question.lower() == "n": #in case of capital letters is entered
    print("oh..okay")
    exit()

# No need of else or elif here because 'n' answers will exit code.
print("I'm thinking of a number between 1 & 10")

[..]

score -1 · Answer 2 · edited Nov 01 '18 at 00:15

-1

Try putting your question code in a function. Like this:

def ask():
    question = input("Would you like to play a game? [Y/N] ")
    if question.lower() == "n": #in case of capital letters is entered
        print("oh..okay")
        exit()
    elif question.lower() == "y":
        print("I'm thinking of a number between 1 & 10")
    else:
        ask()

edited Nov 01 '18 at 00:15

Alfe

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answered Nov 01 '18 at 00:12

Keith Cronin

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Sorry about the poor indentation. I'm sure you get the idea. – Keith Cronin Nov 01 '18 at 00:12
2

Rather than aplogising for the poor indentation, you could edit your answer to fix it? – DavidG Nov 01 '18 at 00:14
1

Rather than asking for fixing it, I fixed it. – Alfe Nov 01 '18 at 00:16

Ask for correct input untill it is given in python

2 Answers2