Generate a random number in interval [0,360) which is divisible by number 15

Question

I am wondering how to generate a number in interval of [0,360) which would be also divisible by number 15. Examples: 0, 15, 30, 45, 50.. I can generate a number in the interval with:

    (int)(Math.random()*360));

But I don't know how to make sure that the generated number is divisible by number 15.

Given that your intended integer is `n`, consider the range that `n/15` will fall into. This should then lead to a clear next step. — nanofarad, Nov 01 '18 at 20:21

score 2 · Accepted Answer · answered Nov 01 '18 at 20:22

2

Welcome to SO Michal!

One easy way to accomplish this is to generate a random number less than 24 (=360/15), then multiply the result by 15:

(int)(Math.random()*24)) * 15;

answered Nov 01 '18 at 20:22

nvioli

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score 2 · Answer 2 · answered Nov 01 '18 at 20:22

2

Taking some information from this previous question, you can just generate a random number between the range 0 to 24 and multiply it by 15.

answered Nov 01 '18 at 20:22

AbsoluteSpace

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Generate a random number in interval [0,360) which is divisible by number 15

2 Answers2