How to print a list of numbers without square brackets?

Question

I'm generating a list of random digits, but I'm struggling to figure out how to output the digits in a single row without the square brackets?

import random 
def generateAnswer(answerList):

    listofDigits = []
    while len(listofDigits) < 5:
        digit = random.randint(1, 9)
        if digit not in listofDigits:
            listofDigits.append(digit)
    return listofDigits

def main():
    listofDigits = []
    print(generateAnswer(listofDigits))

main()

Hi, there are a few optimizations you can do. Please check out my answer :) — Pinyi Wang, Nov 02 '18 at 01:35
Does this answer your question? [Print list without brackets in a single row](https://stackoverflow.com/questions/11178061/print-list-without-brackets-in-a-single-row) — Gino Mempin, Jan 03 '22 at 23:50

tike · Answer 1 · 2018-11-02T01:22:12.267

4

print(", ".join([str(i) for i in generateAnswer(listofDigits)]))

edited Nov 02 '18 at 01:22

answered Nov 02 '18 at 01:19

tike

2,234
17
19

TypeError: sequence item 0: expected str instance, int found – rassar Nov 02 '18 at 01:20

score 4 · Accepted Answer · answered Nov 02 '18 at 01:21

4

You can unpack a list and use the sep argument:

print(*generateAnswer(listofDigits), sep=' ')

answered Nov 02 '18 at 01:21

jpp

159,742
34
281
339

4

that's even better! – tike Nov 02 '18 at 01:22

Pinyi Wang · Answer 3 · 2018-11-02T01:33:47.850

3

Try this:

listofDigits = []
print(str(generateAnswer(listofDigits))[1:-1])

Also, if generateAnswer initialize and return the list, then you don't need to pass in an empty list. Another thing is that if you want to generate a non-repeating random list, you can use random.sample and range.

I think this is better:

import random 
def generateAnswer():
    return random.sample(range(1, 10), 5)

def main():
    print(str(generateAnswer())[1:-1])

main()

Hope it helps!

edited Nov 02 '18 at 01:33

answered Nov 02 '18 at 01:23

Pinyi Wang

823
5
14

probably the version with the least allocations – tike Nov 02 '18 at 01:25

score 1 · Answer 4 · answered Nov 02 '18 at 01:21

The reason you’re getting the brackets is because the list class, by default, prints the brackets. To remove the brackets, either use a loop or string.join:

>>> print(' '.join(map(str, listofDigits)))
9 2 1 8 6
>>> for i in listofDigits:
    print(i, end=' ')


9 2 1 8 6

Note that the last method adds a space at the end.

Note that in the first method, the arguments need to be cast to strings because you can only join strings, not ints.

How to print a list of numbers without square brackets?

4 Answers4

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