Run spring boot from shell script and print URL on the console

Question

I have shell script which is simply building and deploying my spring boot app.

Within this script I have only 1 command:

mvn spring-boot:run

Is it possible to print URL under which my app was deployed after deployment is successfully finished? The best would be if I can obtain this URL somehow and print it on the console.

EDIT I used following solution

@Component
public class ListenerContainer {

    @Autowired
    Environment environment;

    private Logger logger = LoggerFactory.getLogger(ListenerContainer.class);

    @EventListener(ApplicationReadyEvent.class)
    public void postStartupPrint() throws UnknownHostException {
        logger.info("Application deployed under: http://"
                + InetAddress.getLocalHost().getHostAddress()
                + ":"
                + environment.getProperty("local.server.port"));
    }
}

You can try "[Launch browser automatically after spring-boot webapp is ready](https://stackoverflow.com/questions/27378292/launch-browser-automatically-after-spring-boot-webapp-is-ready)", pass your hostname depending on environment & some endpoint you wish. — buræquete, Nov 03 '18 at 12:20
I don't want to launch browser. I need this url on the console. — piechos, Nov 03 '18 at 12:24

buræquete · Accepted Answer · 2018-11-03T12:38:38.443

You can log the url after your context is ready, which can be seen during mvn spring-boot:run

@Component
public class ListenerContainer {

    // autowire & get logic for hostname & context path

    @EventListener(ApplicationReadyEvent.class)
    public void postStartupPrint() {
        System.out.println(hostname + contextPath + "/actuator/health");
    }
}

where hostname can be gathered from here, and contextPath from here

This is just an idea, I have no environment to test, hope it would help!

Run spring boot from shell script and print URL on the console

1 Answers1