Get sum of arrays inside array

Question

How do I get the sum of this arrays.

$arrays = [[0, 176000], [0,500], [0, 3960000]];

The output should be:

$arrays = [0, 4136500];

Any help will be much appreciated.

your array is wrong otherwise your output is not right! – Jignesh Joisar Nov 05 '18 at 07:29 — Jignesh Joisar, Nov 05 '18 at 07:29
`,` is elements delimiter in array. Numbers don't use it. – u_mulder Nov 05 '18 at 07:32 — u_mulder, Nov 05 '18 at 07:32
Okay already updated my arrays. – Jearson Nov 05 '18 at 07:33 — Jearson, Nov 05 '18 at 07:33
What have you tried so far? – Nigel Ren Nov 05 '18 at 07:34 — Nigel Ren, Nov 05 '18 at 07:34

score 2 · Answer 1 · answered Nov 05 '18 at 07:34

2

Using variadic arguments and null callback for first array_map:

$arrays = [[0, 176000], [0,500], [0, 3960000]];
print_r(array_map('array_sum', array_map(null, ...$arrays)));

answered Nov 05 '18 at 07:34

u_mulder

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Im getting this error: "array_sum() expects parameter 1 to be array, integer given" – Jearson Nov 05 '18 at 07:37
@u_mulder I used return instead of print_r. – Jearson Nov 05 '18 at 07:42
As @Nick provides a __working__ fiddle, then I suppose you showed us not correct data or applied my code wrong. – u_mulder Nov 05 '18 at 07:55

Egretos · Answer 2 · 2018-11-05T08:03:04.317

0

In Larevel you can use collections. For example:

    $a = collect([[0, 176000], [0,500], [0, 3960000]]);
    $b = new Collection;
    foreach ($a as $k => $e) {
        $b->push ( $a->pluck($k)->sum() );
    }

    $c = $b->take(2); // Result is going to be here

edited Nov 05 '18 at 08:03

answered Nov 05 '18 at 07:49

Egretos

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7
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Thanks. But I'am getting 3 items [ 0, 4136500, 0 ]. It should be [ 0, 4136500 ] – Jearson Nov 05 '18 at 07:59
However the $b->take(2) would be dynamic I can take 3 – Jearson Nov 05 '18 at 08:05
In your case try to use `$c = $b->take($e->count());` in loop. – Egretos Nov 05 '18 at 08:09
the $e is out of scope? – Jearson Nov 05 '18 at 08:27

score 0 · Answer 3 · answered Nov 05 '18 at 08:15

0

this is using native way (but i think need to rework)

<?php
$arrays = [[0, 176000], [0,500], [0, 3960000]];
$new_arrays = [];
foreach ($arrays as $key => $val) {
  $new_arrays[0] += $val[0];
  $new_arrays[1] += $val[1];
}
print_r($new_arrays);

answered Nov 05 '18 at 08:15

ilubis

141
1
7

Thanks. I think so because the array index should be dynamic. – Jearson Nov 05 '18 at 08:17
can you more specific on what do want to achieve? @Jearson – ilubis Nov 05 '18 at 08:22
$ilubis what if I have [[0,17600, 200]] – Jearson Nov 05 '18 at 08:26

score 0 · Answer 4 · answered Nov 05 '18 at 08:40

0

U_mulders answer works if there is no keys to to keep track of.

If you have an associative array then you need to loop the array and build add the values like:

$arrays = [[0,"A" => 176000], [0, "b" => 500], [0, 3960000, 200], [10, 500, 200]];

foreach($arrays as $sub){
    foreach($sub as $key => $num){
        if(!isset($new[$key])) $new[$key] =0;
        $new[$key] += $num;
    }
}
var_dump($new);

Output:

array(5) {
  [0]=>
  int(10)
  ["A"]=>
  int(176000)
  ["b"]=>
  int(500)
  [1]=>
  int(3960500)
  [2]=>
  int(400)
}

https://3v4l.org/NbNVg

answered Nov 05 '18 at 08:40

Andreas

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Yeah mulder answer is correct for native php but for collections in laravel converting to Array is not working – Jearson Nov 05 '18 at 08:46
@Jearson What are you converting? Your question says nothing about converting – Andreas Nov 05 '18 at 08:53

score 0 · Answer 5 · answered Apr 21 '22 at 16:33

There is no need to call array_map() more than once. Unpack the array using the spread operator (...). This will deliver columns of data to the custom function's body. Return the sum of each column.

Code: (Demo)

$arrays = [[0, 176000], [0,500], [0, 3960000]];
var_export(
    array_map(fn() => array_sum(func_get_args()), ...$arrays)
);

Or

var_export(
    array_map(fn(...$col) => array_sum($col), ...$arrays)
);

Output (from either)

array (
  0 => 0,
  1 => 4136500,
)

Get sum of arrays inside array

5 Answers5

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