How to Convert Decimal to Binary without arrays or recursion?

Question

i'm trying to convert decimal to binary without any arrays or without recursion. I'm aware of the one command that you can use to convert decimal to binary but i'm trying to do this manually. Any help would be appreciated.

   public class Decimaltobinary {

    public static String decimalToBinary(int valueIn){

        //    String binaryOut = "";
        //    int counter = 0;
        int remainder, i = 0;

        while (valueIn != 0){
            remainder = valueIn % 2;
            valueIn /= 2;
            int binaryNum += remainder * i;
            i *= 10;
        }
        return binaryNum;

    }

    /**
    * @param args the command line arguments
    */

    public static void main(String[] args) {
        // TODO code application logic here
        Scanner keyboard = new Scanner (System.in);
        System.out.println("Please enter the decimal number: ");
        int valueIn = keyboard.nextInt ();
        String outputOut = decimalToBinary(valueIn);
        System.out.println ("The output is: " +outputOut);    
    }

}

I'm getting an error for the return BinaryNum statement that says 'cannot find symbol' and an error for the

 int binaryNum += remainder * i;

statement. The error says '; expected'.

You know about `Integer.toBinaryString()` right? Just checking to make sure you're re-implementing it on purpose. — markspace, Nov 05 '18 at 18:54
So this method has real problems. Your method returns a string but you are trying to return in integer. Can't do that. Please fix the obvious syntax errors in your code first. — markspace, Nov 05 '18 at 18:56
@markspace i do know about it yes. i don't want to use that function but rather, make one of my own. — Liz Mcguire, Nov 05 '18 at 18:59

Ryuzaki L · Accepted Answer · 2018-11-05T19:46:33.513

1

you declared binaryNum inside while loop so the scope of this variable will be inside the loop only, declare it outside the while loop and change binaryNum type to String

public class Decimaltobinary {

public static String decimalToBinary(int valueIn){

     //    String binaryOut = "";
     //    int counter = 0;
      int remainder, i = 0;
       String binaryNum ="";
      while (valueIn != 0){
        remainder = valueIn % 2;
        valueIn /= 2;
        binaryNum = remainder+binaryNum;
      }
     return binaryNum;
}

/**
* @param args the command line arguments
*/

public static void main(String[] args) {
    // TODO code application logic here
    Scanner keyboard = new Scanner (System.in);
    System.out.println("Please enter the decimal number: ");
    int valueIn = keyboard.nextInt ();
    String outputOut = decimalToBinary(valueIn);
    System.out.println ("The output is: " +outputOut);    
   }

}

edited Nov 05 '18 at 19:46

answered Nov 05 '18 at 18:59

Ryuzaki L

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that fixed the error, but its still giving me an error on the 'return binaryNum' command – Liz Mcguire Nov 05 '18 at 19:04
change `binaryNum` type to string since your return type is string – Ryuzaki L Nov 05 '18 at 19:06
okay that works great, thanks for that. however, if you input 10, it outputs 0000. it should be 00001010. what am i doing wrong? – Liz Mcguire Nov 05 '18 at 19:09
updated you don't need to multiply with `i` always, this gets output in 4 bits – Ryuzaki L Nov 05 '18 at 19:18
How would i do it differently? – Liz Mcguire Nov 05 '18 at 19:24
differently means? be more clear, just think 1*0 or 0*0 or 0*1 is 0 only – Ryuzaki L Nov 05 '18 at 19:25
How would I do it without `i` ? – Liz Mcguire Nov 05 '18 at 19:27
updated my code gives you result in check it once – Ryuzaki L Nov 05 '18 at 19:28
do you mind editing it so that it takes the user's input and then converts? – Liz Mcguire Nov 05 '18 at 19:43
That code is already available in your main method right? you can use that let me update – Ryuzaki L Nov 05 '18 at 19:45

How to Convert Decimal to Binary without arrays or recursion?

1 Answers1