Print the unique values of all columns of a dataset in R

Asked Nov 06 '18 at 13:07

Active Nov 06 '18 at 13:15

Viewed 321 times

So what I've bee trying to do here is to get the unique values of all the columns,

 i = 1
for (i in i : ncol(usd_empatt_dataset))
{
  cat(names(usd_empatt_dataset[i])," has ", colSums(is.na(usd_empatt_dataset[i])),"\n")
}

The code executes fine.

But i get the following error

Error in print.default(names(usd_empatt_dataset[i]), " has ", unique(usd_empatt_dataset[3]),  : 
  invalid 'digits' argument
In addition: Warning message:
In print.default(names(usd_empatt_dataset[i]), " has ", unique(usd_empatt_dataset[3]),  :
  NAs introduced by coercion

Kindly share some fix and knowledge on the same. Thanks in Advance :)

edited Nov 06 '18 at 13:15

zx8754

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asked Nov 06 '18 at 13:07

Shhiv

1

Maybe `lapply(myData, unique)` ? – zx8754 Nov 06 '18 at 13:11
or `apply( dyData, 2, unique )` – Wimpel Nov 06 '18 at 13:12
Possible duplicate of [unique() for more than one variable](https://stackoverflow.com/questions/7790732/unique-for-more-than-one-variable). – Tim Biegeleisen Nov 06 '18 at 13:12
At the moment I think your code is getting count of non NA values in every column... What is the expected output? – zx8754 Nov 06 '18 at 13:14

Print the unique values of all columns of a dataset in R

0 Answers0