When I execute the below command in python, the console gives an error Note: I am working windows 10 environment
>>> os.listdir()
Traceback (most recent call last):
File "<stdin>, line 1, in <module>
TypeError: listdir() takes exactly 1 argument (0 given)
You need to use listdir() with a path like:
#!/usr/bin/python
import os
# Open a file
path = "/var/www/html/"
dirs = os.listdir(path)
# This would print all the files and directories
for file in dirs:
print(file)
I think you want to use
os.listdir(os.getcwd())
This lists the current working directory (os.getcwd() returns the path)
This TypeError: listdir() takes exactly 1 argument (0 given) generally doesn't occur when you run the same command in Jupyter Notebook as path variables are already settled up when you launch a notebook. But you are running .py scripts you can sort it below way.
import os #importing library
path=os.getcwd() #will return path of current working directory in string form
a=os.listdir(path) #will give list of items in directory at <path> location same as bash command "ls" on a directory
Or you can manually give path as,
import os
path='/home/directory1/sub_directory'
a=os.listdir(path)
You can print a to checkout
print(a)
Instead of os.listdir(), os.walk() is a way better alternative -
path = 'set/to/your/path'
filetups = [(r,f) for r,d,f in os.walk(path)]
print([i+'/'+k for i,j in filetups for k in j])
This should give you a complete list of the file paths under the path you want to explore.
