How i convert number HEX with base 1 (0x1) to base 2 (0x01).
Hex_B1 = 0x1 Hex_B2 = 0x01
hex(int('110', 2)) = 0x06
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I think you mean you want leading zeros? – Stephen C Nov 12 '18 at 17:34
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If you Google the phrase "Python convert hex to binary", you’ll find tutorials that can explain it much better than we can in an answer here. – Prune Nov 12 '18 at 17:36
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You are using the wrong terminology here. Hex is a base 16 numerical notation, *base 2* is binary. You are instead trying to format hexadecimal to using 2 *digits*, padding with zero as needed. – Martijn Pieters Nov 12 '18 at 17:37
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@GuiLuiz You mean converting _binary_ (base 2) to hex (base 16) ? – p._phidot_ Nov 12 '18 at 17:37
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Because hex produces a string, you can just parse the string after conversion to hex.
leading_zeros = 2
str_hex = hex(int('110', 2))
final_hex = '0x'+str_hex[2:].zfill(leading_zeros)
As pointed out by Martijn Pieters in the comments, the much better solution is to use Pythons built in format function.
format(5, '#04x')
Stephen C
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1The correct solution is to not use the `hex()` function to begin with. `format(value, '#04x')` would give you the correct format without string concatenation and `str.zfill()` calls. – Martijn Pieters Nov 12 '18 at 17:39
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@Martijn maybe with a `value & 0xFF` if needing to restrict - depends what the OP's really after though... – Jon Clements Nov 12 '18 at 17:41
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@MartijnPieters Much better solution (though you actually need `'#04x'). Thanks for pointing this out. – Stephen C Nov 12 '18 at 17:44
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@Stephen: ah yes, I always forget to adjust the full width when adding `#`... – Martijn Pieters Nov 12 '18 at 17:46