while making a card game how can i make it so you cant draw the same card twice

Question

Im trying to figure out how to get the program to recognize what card was drawn and remove it from the deck so it cant be drawn again. I know I could have don't a list of 52 where I have each item be a card name and pull it from that list and put it in a new list but with the way I did this that doesn't seem possible. so how can I make it so it only draws a card one time?

import random
import time

played = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
          0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
          0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
          0,0,0,0,0,0,0]

def loop():
keepLooping = True
while(keepLooping):
    global played
    print ('The player with the lower card goes first')
    print(' ')

    # player One draw
    draw = input("Player one would you like to draw?(y,n): ")
    if draw == 'y':
                 CardNumber = random.randint(2,14)
                 Num2 = random.randint(2,4)
                 Royal = {11: "Jack",12: "Queen",13: "King",14: "Ace"}
                 cardnum1 = Royal.get(CardNumber, CardNumber)
                 suits = {1: "Spades", 2: "Hearts", 3: "Diamonds", 4: "Clubs"}
                 cardnum2 = suits[Num2]
                 DrawOne = [cardnum1, cardnum2]
                 print(DrawOne)
                 print(' ')
    if draw == 'n':
        print ('ok')

    # player two draw
    draw = input("Player Two would you like to draw?(y,n): ")
    if draw == 'y':
                 CardNumber2 = random.randint(2,13)
                 Num3 = random.randint(2,4)
                 Royal = {11: "Jack",12: "Queen",13: "King",14: "Ace"}
                 cardnum3 = Royal.get(CardNumber2, CardNumber2)
                 suits = {1: "Spades", 2: "Hearts", 3: "Diamonds", 4: "Clubs"}
                 cardnum4 = suits[Num3]
                 DrawTwo = (cardnum3, cardnum4)
                 print(DrawTwo)
    if draw == 'n':
        print ('Then you lose')

    # Win/lose/tie   
    if CardNumber == CardNumber2:
        time.sleep(1)
        print(' ')
        print("it was a tie, lets re-draw")
        print(' ')
        keepLooping = True
    else:
        if CardNumber < CardNumber2:
            keepLooping = False
            time.sleep(.5)
            print(' ')
            print (DrawOne, 'Is the lower card, player 1 youre going first')
        if CardNumber > CardNumber2:
            keepLooping = False
            time.sleep(.5)
            print(' ')
            print (DrawTwo, 'Is the lower card, player 2 youre going first') 

    loop()

Answer 1

Easy way conceptually (and not using numpy):

>>> cards = list(range(52))
>>> random.shuffle(cards)
>>> cards
[7, 28, 1, 49, 27, 36, 26, 16, 32, 23, 45, 19, 31, 13, 44, 5, 37, 3, 39, 29, 42, 11, 46, 6, 2, 0, 15, 14, 48, 38, 9, 51, 10, 20, 43, 25, 18, 12, 8, 21, 47, 4, 33, 24, 41, 50, 35, 17, 40, 22, 34, 30]

Now everytime you draw, you can pop one from the list.

>>> card = cards.pop()
>>> card
30

Then to get the suit and the number, you can do this:

suit = card % 4        # e.g. 0 is hearts, etc. (arbitrary)
number = card % 13 + 1 # so that 1 is 1, and 11 is Jack

In case modulo (%) is not familiar, please have a look here: How does % work in Python?