Error trying to load image from JSON file to php

Question

So, im trying to display the images that are in my JSON file on my website by calling the json file into my php but i get this notice "Array to string conversion". Any ideas on how i should solve this problem?

JSON

[
{
"name" : "match numbers 1",
"template" : "matching",
"data" : [
  [
   "one",
   "Images/Number1.jpg"
  ],
  [
   "four",
   "Images/Number4.jpg"
  ],
  [
   "nine",
   "Images/Number9.jpg"
  ]
]
},

{
"name" : "match numbers 2",
"template" : "matching",
"data" : [
  [
   "six",
   "Images/Number6.jpg"
  ],
  [
   "eight",
   "Images/Number8.jpg"
  ],
  [
   "nine",
   "Images/Number9.jpg"
  ]
]
  }
]

php code

<?php
  $json_var = file_get_contents("template.json");
  $json_var = json_decode($json_var, true);
  foreach($json_var as $value)
  {
    printf($value["name"]);
    printf($value["template"]);
    printf('<img src="'.$value["data"].'" />');
  }
?>

`$value["data"]` is an array, it contains more than one image. You'll need a nested loop. — Alex Howansky, Nov 14 '18 at 16:11

suresh bambhaniya · Accepted Answer · 2018-11-14T16:19:30.253

2

because $value["data"] is array so you can iterate and get all images

<?php
  $json_var = file_get_contents("template.json");
  $json_var = json_decode($json_var, true);
  foreach($json_var as $value)
  {
    printf($value["name"]);
    printf($value["template"]);
    foreach($value["data"] as $val){
     printf('<img src="'.$val[1].'" />'); //$val is also array, i assumed second is image url 
    }
  }
?>

edited Nov 14 '18 at 16:19

answered Nov 14 '18 at 16:12

suresh bambhaniya

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1

Thank you for the help! it worked – Noob Programmer Nov 14 '18 at 16:28
If solution is works then please mark as correct/upvote then future user easily find out correct answer – suresh bambhaniya Nov 15 '18 at 04:27

score 0 · Answer 2 · answered Nov 14 '18 at 16:17

The "Array to string conversion" error is happening because your $value["data"] is an array. You will also want to iterate through that array as well. Something like this.

<?php
  $json_var = file_get_contents("template.json");
  $json_var = json_decode($json_var, true);
  foreach($json_var as $value)
  {
    printf($value["name"]);
    printf($value["template"]);
    foreach($value["data"] as $data){
     printf('<img src="'.$data[1].'" />'); //<- I assume this index
    }
  }
?>

Whenever I see the pesky Array to string conversion. var_dump is my best friend to debug the formatting.

Thanks a lot! I appreciate it – Noob Programmer Nov 14 '18 at 16:28 — Noob Programmer, Nov 14 '18 at 16:28

Error trying to load image from JSON file to php

2 Answers2