how to write regular expression allow name with one space and special Alphabets?
I tried with this [a-zA-Z]+(?:(?:\. |[' ])[a-zA-Z]+)* but not working for me,
example string Björk Guðmundsdóttir
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Vhndaree
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Is that space mandatory or optional? – Tim Biegeleisen Nov 15 '18 at 13:26
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@TimBiegeleisen optional only – Nov 15 '18 at 13:27
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OK, and what are "special" alphabets? I would assume it's a special edition of breakfast cereal, unless you tell me otherwise. – Tim Biegeleisen Nov 15 '18 at 13:27
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1https://shinesolutions.com/2018/01/08/falsehoods-programmers-believe-about-names-with-examples/ – Quentin Nov 15 '18 at 13:27
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Use `/^\S+\s\S+$/` – Mohammad Nov 15 '18 at 13:29
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You may try something along these lines:
^(?!.*[ ].*[ ])[ A-Za-zÀ-ÖØ-öø-ÿ]+$
The first negative lookahead asserts that we do not find two spaces in the name. This implies that at most one space is present (or no spaces at all). Then, we match any number of alphabets, with most accented letters included. Spaces can also be matched, but the lookahead would already ensure that at most one space can be present.
Tim Biegeleisen
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Arthur
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Replace {1} with ? sign for 0 or 1 space included. [a-zA-Z\u00C0-\u00ff]*\s?[a-zA-Z\u00C0-\u00ff]* – Arthur Nov 15 '18 at 13:34