Do any command line parameters pass when invoking program as myCopy file1.txt file2.txt file3.bin in C?

Asked Nov 17 '18 at 20:34

Active Nov 17 '18 at 20:43

Viewed 27 times

I'm specifically confused about the agrc and argv here. I know argc contains number of arguments with programs name being first and argv is the array of pointers that are strings.

However, in this case, will argv[argc] contain any command line parameters or not? Shouldn't argv[1] contain myCopy?

asked Nov 17 '18 at 20:34

Toby

2

give it a try: write a program that prints out argc and all the items in argv. that will help you see how this works. – jdigital Nov 17 '18 at 20:37
arrays start at 0, so `argv[0]` contains the command name. `argv[argc]` should not be accessed as it's outside array bounds or maybe contains NULL, not sure now – Jean-François Fabre Nov 17 '18 at 20:40
Create a loop from `0` (don't forget array indexes are zero-based) to `argc - 1` (inclusive), and print all elements of `argv` with those indexes. – Some programmer dude Nov 17 '18 at 20:41
`argv[argc]` is equivalent to `array[arraylen]`, which you probably know is out of bounds (this is why `for` loops run `< length`). – ggorlen Nov 17 '18 at 20:41
@ggorlen The `argv` array is a special case, where `argv[argc]` is specified to always be a `NULL` pointer. – Some programmer dude Nov 18 '18 at 05:54
@Someprogrammerdude Nice to know – ggorlen Nov 18 '18 at 05:57

Do any command line parameters pass when invoking program as myCopy file1.txt file2.txt file3.bin in C?

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