How to send UITableViewCell data to another ViewController in swift?

Question

I am trying to send a single message from the messageArray to another UIViewController so that I can load up the message's comments. How can I send the message data structure over when the cell is clicked on?

func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
        guard let cell = tableView.dequeueReusableCell(withIdentifier: "messageCell") as? feedMessagesCell else {return UITableViewCell()}


        let message = messageArray[indexPath.row]
        cell.configureCell(content: message.content, userName: message.userName)
return cell

    }

You can refer to this answer. https://stackoverflow.com/a/26374173/8330469 — Nilanshu Jaiswal, Nov 18 '18 at 08:25

score 3 · Accepted Answer · answered Nov 18 '18 at 08:11

First of all don't guard reusing cells. The code must not crash. If it does it reveals a design mistake. And use the API which returns a non-optional cell.

let cell = tableView.dequeueReusableCell(withIdentifier: "messageCell", for: indexPath) as! feedMessagesCell

To send data to another view controller create a segue in Interface Builder by connecting the table view cell to the destination controller.

In prepare(for segue the sender is the cell. Change PushFeedDetail to the real identifier and MyDestinationController to the real class. Create a message property in the destination controller. Get the index path from the cell and pass the item in the data source array.

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
    if segue.identifier == "PushFeedDetail" { 
        let selectedIndexPath = tableView.indexPath(for: sender as! feedMessagesCell)!
        let destinationController = segue.destination as! MyDestinationController
        let message = messageArray[selectedIndexPath.row]
        destinationController.message = message
    }
}

How to send UITableViewCell data to another ViewController in swift?

1 Answers1