JQuery Event is not a function

Question

When I use the following "jquery.event" line:

var newevent= jQuery.Event("keypress").which(40).keycode(40);

...I get the following error:

Uncaught TypeError: jQuery.Event(...).which is not a function

How can I prevent this error?

Further clarification:

When the two lines I use are:

  var newevent= jQuery.Event("keypress").which(40).keycode(40);
  $('#juris1 .selectpicker').trigger(newevent);

This code triggers the event (and opens a select box), but I get the error.

When I use the standard way from the API documentation, I no longer get an error, but the code does not trigger the keypress

var newevent = jQuery.Event("keypress", { keyCode: 40, which: 40 });

So use it the right way: https://api.jquery.com/category/events/event-object/ — epascarello, Nov 19 '18 at 15:06

hawkstrider · Answer 1 · 2018-11-19T16:30:07.517

0

Per the documentation... https://api.jquery.com/category/events/event-object/

var newevent = jQuery.Event( "keypress", { keyCode: 40 } );

Per this post Definitive way to trigger keypress events with jQuery

var newevent = jQuery.Event("keypress");
newevent.keyCode = newevent.which = 40; // # Some key code value
$('#juris1 .selectpicker').trigger(newevent);

edited Nov 19 '18 at 16:30

answered Nov 19 '18 at 15:07

hawkstrider

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Thanks. Error is gone, but now the keypress won't trigger (which would happen with the old code) – user749798 Nov 19 '18 at 16:01

JQuery Event is not a function

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