Removing width and height from img tag with preg_replace results in null value

Asked Nov 19 '18 at 20:07

Active Nov 19 '18 at 20:07

Viewed 22 times

I'm working with an image that's processed through a long script in which I cannot modify the function so I'm looking to simply process it's output afterwards with a regex. Here's what I've got:

I have the following regex pattern:

'width\=\"(.*?)\"\sheight\=\"(.*?)\"'

I'm trying to remove the width and height from an image tag much like this:

<img width="706" height="452" src="/images/logos/partner.png" />

When using preg_replace function like so:

$img['thumbnail'] = preg_replace(
    'width\=\"(.*?)\"\sheight\=\"(.*?)\"',
    '', 
    $img['thumbnail']);

However this returns NULL.

I've tested this using https://regex101.com/ and it appears to be valid. What am I missing?

asked Nov 19 '18 at 20:07

Chris Stage

1

In PHP regexps, you must use delimiters. E.g. `$rx = '~pattern~';` – Wiktor Stribiżew Nov 19 '18 at 20:08
Need regex delimiters, can be anything, `'/width="(.*?)\ssheight="(.*?)"/'` or `'~width="(.*?)\ssheight="(.*?)"~'` or `'#width="(.*?)\ssheight="(.*?)"#'` , etc ... – Nov 19 '18 at 20:49
Is there a reason why you would choose one delimiter over the other? – Chris Stage Nov 19 '18 at 21:02

Removing width and height from img tag with preg_replace results in null value

0 Answers0