Print returning memory address in python

Question

When I'm trying to print matrix1, the output is the memory address of the object.

print("enter n for nxn matrix")
n = int(input())

matrix1 = []
matrix2 = []

#taking elements of first matrix

print("Enter elements of first matrix")
for i in range(0,n):

  #taking elements of first column

  print("Enter elements of ",i,"column, seperated by space")

  #raw_input().split() will split the string
  #'1 2 34'.split() will give ['1', '2', '34']
  #map will convert its elements into integers [1, 2, 34]

  matrix1.append(map(int,input().split()))

print("Matrix 1 is",matrix1)
print(matrix1)

Ouput recieved.

enter n for nxn matrix
2
Enter elements of first matrix
Enter elements of  0 column, seperated by space
2 3
Enter elements of  1 column, seperated by space
4 5
Matrix 1 is [<map object at 0x101834898>, <map object at 0x1032d2f60>]

Not sure why the memory address of the object is being printed. I'm using python3.

`map` in python 3 return `map` object. If you want to convert it into a `list` you should call `list` function on it. — Abdul Niyas P M, Nov 20 '18 at 06:59
Possible duplicate of [Getting a map() to return a list in Python 3.x](https://stackoverflow.com/questions/1303347/getting-a-map-to-return-a-list-in-python-3-x) — b-fg, Nov 20 '18 at 07:00

score 0 · Answer 1 · answered Nov 20 '18 at 07:03

0

map returns itself (or perhaps it is better to say it returns an object of its type?) but you can still iterate through it:

j = [1, 2, 3, 4]
j = map(lambda x: x+1, j)
{x for x in j}

Gives:

{2, 3, 4, 5}

answered Nov 20 '18 at 07:03

Charles Landau

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Print returning memory address in python

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