String.replace and "$1"

Asked Nov 20 '18 at 21:24

Active Nov 20 '18 at 21:29

Viewed 326 times

I recently wrote a variable parsing framework that up until now, worked very well. When writing some financial tracking software using this framework, I ran into the following issues.

If:

string="%{data}";

Then:

console.log(string.replace(/%\/?{(\S[^\%{}]*)}/,"$5000"));

Yields $5000.

This is how it is intended to work.

However, if I try the following:

console.log(string.replace(/%\/?{(\S[^\%{}]*)}/,"$15000"));

I get data5000.

I'm guessing that $1 is a variable used within JavaScripts replace() method. Am I right? If so, is there anyway I can change String.prototype.replace() to use another variable? This also leads me to wonder if the scope for the replace method is even declared...

asked Nov 20 '18 at 21:24

Evan Hendler

3

Replace with `"$$15000"`. When you need add a *literal* `$` char to the replacement pattern, use double dollar symbol (it is called dollar-escaping). – Wiktor Stribiżew Nov 20 '18 at 21:25
Thank you so much! – Evan Hendler Nov 20 '18 at 21:28
[Here](https://stackoverflow.com/questions/28102491/javascript-better-way-to-escape-dollar-signs-in-the-string-used-by-string-prot) is another duplicate with a solution for dynamic replacement patterns. – Wiktor Stribiżew Nov 20 '18 at 21:30

String.replace and "$1"

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