Android edittext - do not allow decimal separator alone

Question

I have an Edittext, where I want to allow only numbers and decimal numbers (max 2 decimals after separator e.g. 125.50).

I implemented a filter for this:

 final EditText  field1 = (EditText)findViewById(R.id.field1);
 field1.setFilters(new InputFilter[] { filter });

    InputFilter filter = new InputFilter() {
        final int maxDigitsBeforeDecimalPoint=5;
        final int maxDigitsAfterDecimalPoint=2;

        @Override
        public CharSequence filter(CharSequence source, int start, int end,
                                   Spanned dest, int dstart, int dend) {
            StringBuilder builder = new StringBuilder(dest);
            builder.replace(dstart, dend, source
                    .subSequence(start, end).toString());
            if (!builder.toString().matches(
                    "(([0-9]{1})([0-9]{0,"+(maxDigitsBeforeDecimalPoint-1)+"})?)?(\\.[0-9]{0,"+maxDigitsAfterDecimalPoint+"})?"

            )) {
                if(source.length()==0)
                    return dest.subSequence(dstart, dend);
                return "";
            }

            return null;

        }
    };

This is working fine, but the problem is, that if user inserts decimal separator ALONE, I've got java.lang.NumberFormatException: For input string: "."

In my ontextChanged I tried this:

 if(field1.getText().toString().equals("[.]")){field1.setText(0);}

also this

if(field1.getText().toString().equals(".")){field1.setText(0);}

but did not work.

How can I restrict the decimal separator alone, but allow it with the numbers?

try this `^[1-9]\d*(\.\d+)?$` regex it allows numbers with an optional decimal point followed by digits. A digit in the range 1-9 followed by zero or more other digits then optionally followed by a decimal point followed by at least 1 digit: — karan, Nov 21 '18 at 09:16

score 1 · Accepted Answer · answered Nov 20 '18 at 21:52

If this:

if(field1.getText().toString().equals(".")){field1.setText(0);}

is your exact code, then for sure it failed because 0 is not a string, it's an integer considered to be a resource id.
So first try this:

if(field1.getText().toString().equals(".")){field1.setText("0");}

If it fails again then consider that a NumberFormatException can be resolved by try/catch like this:

double value = 0.0;
try {
    value = Double.parseDouble(field1.getText().toString());
} catch (NumberFormatException e) {
    field1.setText("0");
    e.printStackTrace();
}

perfect, the .setText("0") fixed it. Thank you! – Darksymphony Nov 21 '18 at 18:27 — Darksymphony, Nov 21 '18 at 18:27

score 1 · Answer 2 · answered Nov 21 '18 at 08:59

1

For References, you can use this link if you want to use InputFilter: https://stackoverflow.com/a/5368816/10396176

For other references, if you want using want to try using textWatcher: https://stackoverflow.com/a/16684661/10396176

answered Nov 21 '18 at 08:59

JEFF

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Android edittext - do not allow decimal separator alone

2 Answers2