Filter the required lines using bash

Question

I have a file named "check", which contains the following,

calendar: A
Des: bad
04/12/2009 00:00
09/11/2010 00:00
calendar: B
Des: bad
04/09/2013 00:00
08/08/2013 00:00
calendar: B1
Des: bad
04/03/2014 00:00
04/02/2014 00:00
calendar: C
Des: bad
04/05/2009 00:00
09/11/2010 00:00

I have to filter only the calendar: B* and the corresponding des and dates and place it in a separate file using bash scripting the above given is an example and the actual file will contain more than 200 lines. I tried

 awk '/calendar: B/{print}' check

as the command gives the tag and not the details below to it. I need to have an command which gives the details too

something like this? grep "calendar: B" -A3 file – Incrivel Monstro Verde Nov 21 '18 at 11:44 — Incrivel Monstro Verde, Nov 21 '18 at 11:44

oguz ismail · Accepted Answer · 2018-11-21T11:59:01.590

0

You can use this awk command.

awk '/^calendar/{p=0} /^calendar: B/{p=1} p' check

edited Nov 21 '18 at 11:59

answered Nov 21 '18 at 11:45

oguz ismail

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awk '/^calendar: B/{x=4}x-->0' check, it worked for the file given above, but the actual files does have many dates(not limited to two), – Vicky Nov 21 '18 at 11:55
updated, try it again. – oguz ismail Nov 21 '18 at 11:59
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Amazing!!!Thanks much – Vicky Nov 21 '18 at 12:07

Filter the required lines using bash

1 Answers1