adding const to member function argument produces compile error

Asked Nov 22 '18 at 15:42

Active Nov 22 '18 at 15:45

Viewed 29 times

I have the following code:

void readTable(const Table& table)
{
  for (auto& r: table)
    {
      auto state = r["UX"] == std::string("Yes");
      std::cout << state << '\n';
    }

}

table is defined as

using Row = std::map<std::string, std::string>;
using Table = std::vector<Row>;

My table read function does not change the Table, so I added the const to the readTable(const Table& table). Compiler does not like this change. Is this not the right way of telling the compiler that the table is not supposed to change ?

asked Nov 22 '18 at 15:42

Ring Zero.

`r["UX"]` requires `r` to be non-const because it may need to add an entry to the map if not already present. – Igor Tandetnik Nov 22 '18 at 15:46
@IgorTandetnik what is the work aroud ? I know that map has that element. – Ring Zero. Nov 22 '18 at 15:47
@RingZero [std::map::find](https://en.cppreference.com/w/cpp/container/map/find)? – Algirdas Preidžius Nov 22 '18 at 15:48

adding const to member function argument produces compile error

0 Answers0