Using list comprehensions, transform all vowels within a string to upper case?

Question

Thanks for your help

Example byron = bYrOn

This is an old homework I'm looking over.

`"".join([letter.upper() if letter in "aeiouy" else letter for letter in string])`? — L3viathan, Nov 22 '18 at 19:48
Alternative, without comprehensions: `string.translate({97:65, 101:69, 105:73, 111:79, 117:85, 121:89})` — L3viathan, Nov 22 '18 at 19:54

score 0 · Answer 1 · answered Nov 22 '18 at 19:59

It is actually preety simple to turn all letters in a string to upper case!

just use the variable name and follow .upper() at the end e.g.

byron="byron"

byron=byron.upper()

however, because you want to give only certain letters the "uppercase" status, you'd want to first assign all vowels:

vowels = set(['a','e','i','o','u'])

then use some python logic to do the rest:

for char in byron:
    if char in vowels:
        Word = Word.replace(char,(char.upper()))
print (Word)

if you want to be quick just copy the code below as it is the complete code used to do your task:

x="byron"
vowels = set(['a','e','i','o','u'])
Word=x
for char in Word:
    if char in vowels:
        Word = Word.replace(char,(char.upper()))
print(Word)

Using list comprehensions, transform all vowels within a string to upper case?

1 Answers1