How to make a checkbox checked and disabled?

Question

I have tried:

<input disabled='disabled' 
checked='checked' 
type='checkbox' 
name='checkTema[]' 
value=".$cat->cat_ID."> ".$cat->name."<br>"

But that won't pick up the value when I send the form

UPDATE

Thanks to a comment I've got a helping answer from another SO question, yet I am not sure how I should be applying the trick, tried the following but not sending the value

echo "<input type='hidden' name='checkTema[]' value='1' >";
echo "<input type='checkbox' checked='checked' disabled='disabled' name='checkTema[]' value=".$cat->cat_ID."> ".$cat->name."<br>";

@SougataBose `readonly` isn't picked up by the input ` ".$cat->name."
";` — rob.m, Nov 23 '18 at 05:41
Possible duplicate of [Can HTML checkboxes be set to readonly?](https://stackoverflow.com/questions/155291/can-html-checkboxes-be-set-to-readonly) — Nick, Nov 23 '18 at 05:42
`readonly` doesn't work on checkboxes. See my flagged duplicate for workarounds for this problem — Nick, Nov 23 '18 at 05:43
I was not aware of that. Then you can use some hidden fields and jquery for this purpose. — Sougata Bose, Nov 23 '18 at 05:44
@Nick thanks, saw that answer, but I don't want to use JavaScript, and I am using wrongly the hidden field trick. See updated question — rob.m, Nov 23 '18 at 05:54

Blue · Answer 1 · 2018-11-23T05:48:57.027

0

If you need to POST disabled checkboxes, I suggest using a hidden input before:

<input type="hidden" name="checkbox_disabled" value="<?php echo $checkbox_value; ?>" /> <== Checked and disabled

Then in your PHP code, you can simply check:

if ($_POST['checkbox']) {
  //Checkbox wasn't disabled on submission
} else {
  //Fallback to using the disabled value:
  $disabledVal = $_POST['checkbox_disabled'];
}

Additionally, you can simply undisable all the elements of the form before submission:

$('form').submit(function() {
    $(this).find('input').attr('disabled', false);
});

See this question/answer for more information on how you can alternatively do this.

edited Nov 23 '18 at 05:48

answered Nov 23 '18 at 05:44

Blue

22,608
7
62
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1

But would it post the values? – Sougata Bose Nov 23 '18 at 05:44
this won't POST the value – rob.m Nov 23 '18 at 05:45
yes thanks, see my updated question, I believe I am using wrongly the hidden field trick. There is another answer on here and also taken from https://stackoverflow.com/a/6905050/1018804 which works by using javascript but I wanted to avoid JS – rob.m Nov 23 '18 at 05:53
@rob.m So is it not working? Your code posted should indeed work. `print_r($_POST);` and show the values. – Blue Nov 23 '18 at 05:54
i've answered myself – rob.m Nov 23 '18 at 05:58
@rob.m So pretty much my answer – Blue Nov 23 '18 at 05:59
yes indeed, yet mine follows the exact code I had and it might be clearer for future users ending up on here. Thanks a lot tho – rob.m Nov 23 '18 at 06:05

score 0 · Answer 2 · answered Nov 23 '18 at 05:48

0

Try return false in onclick event

 <input 
     onclick="return false"
    checked='checked' 
    type='checkbox' 
    name='checkTema[]' 
    value='.$cat->cat_ID.'> ".$cat->name."<br>"

answered Nov 23 '18 at 05:48

bhaghyasandar

516
4
16

well I'll be honest with you, this works as per https://stackoverflow.com/a/6905050/1018804 but I didn't want to use javascript. See my updated question as I believe I used wrongly the hidden field trick – rob.m Nov 23 '18 at 05:52

score 0 · Answer 3 · answered Nov 23 '18 at 05:51

0

Try this code :

<input disabled='disabled' checked='checked' type='checkbox' name='checkTema[]' value="<?php echo $cat->cat_ID;?>"><?php echo $cat->name;?>

answered Nov 23 '18 at 05:51

Bhoomi Patel

777
10
32

score 0 · Answer 4 · answered Nov 23 '18 at 05:58

Thanks to a comment, I've got the solution in another SO question

Then my code changed to:

echo "<input type='hidden' name='checkTema[]' value=".$cat->cat_ID." >";
echo "<input type='checkbox' checked='checked' disabled='disabled'> ".$cat->name."<br>";

How to make a checkbox checked and disabled?

4 Answers4