Decimal and double values are resolving to zero

Asked Nov 23 '18 at 14:12

Active Nov 23 '18 at 14:34

Viewed 49 times

I am expecting weight value to be 0.153846 in the code below. Instead I am getting 0. I tried using double and decimal. period is 10

public static Deque<DateClose> EMAMethod(
    Queue<DateClose> queue,
    Deque<DateClose> firstEMASample, 
    int period)
{
    double weight = (2/(period+1));

    Deque<DateClose> sample = new Deque<DateClose>(firstEMASample.ToArray());
    Deque<DateClose> expoMovingAverageQueue = new Deque<DateClose>(queue.Count() + 1);

    // get the last item or initial MA value from the queue
    DateClose eMA = sample.RemoveFromBack();

The is indeed a duplicate. I did search but did not find this answer.

edited Nov 23 '18 at 14:34

Uwe Keim

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asked Nov 23 '18 at 14:12

Jam66125

2

try `double weight = (2.0/(period+1.0));` – Paul Karam Nov 23 '18 at 14:14
2

`double weight = (2d/(period+1));` otherwise, the calculation is performed as `int` then converted to `double`, resulting in truncation. – spender Nov 23 '18 at 14:14
When you say " I am dividing one double and one integer", which exact operation are you referring to? In C#, a literal `2` gets you an **`int`** ... – AakashM Nov 23 '18 at 14:34
AakashM, I was wrong, there are two integers. I did not realize that. – Jam66125 Nov 23 '18 at 15:04

Decimal and double values are resolving to zero

0 Answers0