sorting list by length of sublist

Question

I have a list with sublist,

mylist = [['loan', 'finance'], ['dealer', 'dealers', 'dealership'], ['Data entry', 'data entry', 'enter data']]

I want to sort by using the length of the sublist, so that the output is expected as

reqlist = [['dealer', 'dealers', 'dealership'], ['Data entry', 'data entry', 'enter data'], ['loan', 'finance']]

I was trying to use sorting function

 def take(element): 
    return len(element)
 reqlist = sorted(reqlist, key = take)

I tried list.sort

 mylist.sort(key=len)

it doesnt work and output 'reqlist' is not as expected and is same as 'mylist'. Any help required.

So what exactly is your question? Did your solution not give you the results you wanted? What did it output vs what did you want it to output? — Cory Kramer, Nov 27 '18 at 14:04
is `reqlist = sorted(data, key=take, reverse=True)` what you are looking for? Because otherwise, it seems to be working — Ma0, Nov 27 '18 at 14:04
as by @Ev.Kounis comment: the sorting works just fine, sorting for length 2,3,3. But you want reverse sorting. — planetmaker, Nov 27 '18 at 14:09

score 0 · Accepted Answer · answered Nov 27 '18 at 14:12

0

reqlist = sorted(mylist, key=len, reverse=True)

answered Nov 27 '18 at 14:12

Vikrant Sharma

1 Answers1