Short way to write or in python

Question

I have this code:

table is a list.

if 'ping' in table or 'pong' in table:
    # Do something here

Is there a shorter way to write this? I don't want to have table duplicated in the if statement.

Answer 1

You can use set.intersection:

if {'ping', 'pong'}.intersection(table):
    # Do something here

Answer 2

You can use map:

>>> table = 'pong'
>>> if any(map(lambda pattern: pattern in table, ['ping', 'pong'])):
...     print('found!')
...
found!

or:

>>> table = 'pong'
>>> if any(pattern in table for pattern in ['ping', 'pong'])):
...     print('found!')
...
found!