Python : call a function with return from other function

Asked Dec 01 '18 at 22:16

Active Dec 01 '18 at 22:16

Viewed 34 times

I have two functions that I want to call one after the other. The return from the first one should be the argument of the second. I don't find the way to do it .

BOARD= [[0]*10]*10

def right (board , start, n):
    board[start[0]]= [0]*start[1] + [1]*(n-start[1])
    endpoint= [start[0], start[1]+n]
    return board , endpoint , n

def down (board, start, n): 
    for j in range (1,n ):
        board[start[1]+j][start[0]]= 1
        endpoint= [start[0]+n, start[1]]
    return board , endpoint , n

# the call 
down(right(BOARD, [0,0],10))

the error is : TypeError: down() missing 2 required positional arguments: 'start' and 'n' *

If someone has an idea please .... Thank you in advance :)

asked Dec 01 '18 at 22:16

Remi-007

3

`down(*right(BOARD, [0,0],10))` -- unpacking – Chris_Rands Dec 01 '18 at 22:17
cool thank you very much :) – Remi-007 Dec 01 '18 at 22:20
1

[FYI](https://stackoverflow.com/q/240178/3001761) – jonrsharpe Dec 01 '18 at 22:24
1

As @jonrsharpe was saying, multiplying references to immutable numbers is fine, `[0]*10`, but to mutable lists is a bad idea. Try something like `[[0]*10 for _ in range(10)]` instead. – gilch Dec 01 '18 at 22:52

Python : call a function with return from other function

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