Rounding double variable

Question

I have the following problem. When I try to round a number from a "double" type, it doesn't work as I expect it.

Consider the following code:

double d = 0.00498;
Console.WriteLine(Math.Round(d, 2)); // prints 0

The result that i am getting is wrong.

The program must print 0.01, and I have tried everything and nothing worked properly.

[Not an exact duplicate, but related](https://stackoverflow.com/a/977807/3181933) — ProgrammingLlama, Dec 05 '18 at 06:44
Come on guys.. have you ever been to forth grade, cant you see that the number is 0.01 ?!? — K.Krunk, Dec 05 '18 at 06:50
It surely will be 0 because you are rounding to 2 digit after decimal, make it .Round(d, 3) so it will become 0.005. — Nakul, Dec 05 '18 at 06:51

fubo · Answer 1 · 2018-12-05T06:57:29.390

3

I think you need a second iteration for your desired result

double d = 0.00498;
double result1 = Math.Round(d, 3, MidpointRounding.AwayFromZero);
double result2 = Math.Round(result1 , 2, MidpointRounding.AwayFromZero);
Console.WriteLine(result2);

because 0.00498 results into 0.005 instead of 0.01

edited Dec 05 '18 at 06:57

answered Dec 05 '18 at 06:50

fubo

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Isn't there a way to do it with only one iteration ? – K.Krunk Dec 05 '18 at 06:54
@K.Krunk - why would you think there is a standard way to do non-standard math? – Corak Dec 05 '18 at 07:26

score 0 · Answer 2 · 2018-12-05T07:07:37.260

0

You expect to it rounds the number up with 2 decimal points.

Math.Ceiling(d * 100) / 100

edited Dec 05 '18 at 07:07

answered Dec 05 '18 at 07:03

This will round `double d = 0.032;` to `0.04` – fubo Dec 05 '18 at 07:06

score 0 · Answer 3 · answered Dec 05 '18 at 10:25

0

The result is coming correct. You can try in excel application.

Regards, Nandkumar S.

answered Dec 05 '18 at 10:25

Nandu

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Rounding double variable

3 Answers3