how to run a python file in a package from Idle?

Question

I have a folder (python package):

app/
   __init__.py
   bases.py
   store.py

in store.py I have a the the code

from .bases import BaseStore

class Store(BaseStore):
    # .. class

Everything works when I run the full project.
How can I run the store.py file itself? Running the file with Idle gives an import error.
How can I run a script in idle which will be aware to its package?

BTW, try to remove dot from `.bases`. Simply try `from bases import BaseStore`. I think you don't need it. — trsvchn, Dec 06 '18 at 14:43
I do need the dot as it is a relative import in the package. @TarasSavchyn This doesnt answer my question, I'm talking about running from idle — user3599803, Dec 06 '18 at 15:10
Are you running `store.py` from `app` folder? or outside of it? — trsvchn, Dec 06 '18 at 15:17
from the app folder. I just right click store.py -> `Edit with IDLE` and then F5 to run — user3599803, Dec 06 '18 at 16:22

score 0 · Answer 1 · answered Dec 06 '18 at 20:04

I am pretty sure that this is not an IDLE issue but one of the interaction between relative imports, sys.path, the current working directory, and how you start python. To find out for sure, add the following at the top of store.py.

import os, sys
print(os.getcwd())
print(sys.path)

Then run your code the two different ways. Also add, at a command line

python /path/to/app/store.py

This list is the equivalent of how IDLE runs your code.

how to run a python file in a package from Idle?

1 Answers1