Is there a way to easily convert numbers in a list into single digits for example
population = ['10001','11111','11010','110001']
into ['1','0','0','0','1']
add each digit in each set and put it in another list like
this
evaluation = [2,5,3,3] (adding up all the 1's up on the first list)
I'm very new to Python so I'm not sure if I'm doing this correctly
One possible way is iterate over the population list and use str.count('character') to count the '1''s in each "number" string:
evaluation = list(item.count('1') for item in population)
evaluation will contain the desired counts:
>>> print(evaluation)
[2, 5, 3, 3]
If you are only dealing with zeros and ones, then @davedwards is a good solution. Count the instances of '1' in each string.
out = [x.count('1') for x in population]
If you need the solution to be more extensible to values other than 0 and 1, you can convert each digit to an int and sum the integers.
out = [sum(map(int, x)) for x in population]
Using collections.Counter():
>>> from collections import Counter
>>> population = ['10001','11111','11010','110001']
>>> [Counter(x).get('1', 0) for x in population]
[2, 5, 3, 3]
A functional aproach would be to also use map() and operator.itemgetter():
>>> from collections import Counter
>>> from operator import itemgetter
>>> list(map(itemgetter('1'), map(Counter, population)))
[2, 5, 3, 3]
