UnboundLocalError while return : Python

Question

I have a python boto3 code as below:

for rule in event_rules:
        if rule.startswith('Something'):
            print('[INFO] Proceeding!...')
            describe_rule = self.cw_event.describe_rule(
                Name=rule
            )
            if describe_rule['State'] == 'ENABLED':
                state = True
                break
        else:
            state = False
    return state
    .
    .
    .
if check == True:
       print('[INFO] SUCCESS' )          

else:
       print('[INFO] FAILED')

Here check is the class function which calls the above block from its function.I am pretty confident on the function and class part. In this case when a rule is present and is in ENABLED state,code is successfull. If the conditions are not matching, it throws out an error as follows:

UnboundLocalError: local variable 'state' referenced before assignment

I am not able to figure it out. I went through this answer : UnBoundLocalError: Local Variable Referenced Before Assignment [Counter] and gave state as global, but still failed.

You should specify which line throws the error, the exception should tell you. — Bernhard, Dec 10 '18 at 14:23
@Bernhard error throws at ```return state```; line number 12 — Ebin Davis, Dec 10 '18 at 14:35
In that case, see my anwser, if you hit the first, but miss the second if statement, `state` is not yet assigned . — Bernhard, Dec 10 '18 at 14:39
@Bernhard but even if the first if cases fails, throws the same error. — Ebin Davis, Dec 10 '18 at 14:56

score 0 · Answer 1 · answered Dec 10 '18 at 14:24

As mentioned in the comments, you should probably specify where the exception gets thrown, but at first look, if you get into if rule.startswith('Something'): but don't hit the second if statement [State] == 'ENABLED' then state won't be initiated and might throw the error on the return statement.

UnboundLocalError while return : Python

1 Answers1