gsub for no square brackets or backslashes

Question

I'm currently retrieving this back

":root{--[{\"name\":\"--font\",\"value\":\"Arial\"},{\"name\":\"--bg\",\"value\":\"black\"}]:;}"

I want this same output but with not backslashes or square brackets.

I've done gsub(/\[/,'') but it's not getting rid of the right square bracket. I know adding a right bracket after the left will mean something totally different with regex.

Use `s = s.gsub(/[\]\[]/,'')`. Also, there are no backslashes in your *string*, there are backslashes in your string literal. — Wiktor Stribiżew, Dec 10 '18 at 16:47
@WiktorStribiżew is it not opposite to what user asked for ? — Code Maniac, Dec 10 '18 at 16:51
@WiktorStribiżew `gsub(/[\[\\\]]/,'')` i tried this but i don't know why it is not replacing `\\` when i try to check in tester it is matching properly. link https://repl.it/repls/WarmheartedLeanBoards — Code Maniac, Dec 10 '18 at 16:53
@CodeManiac There are no backslashes in the `str = ":root{--[{\"name\":\"--font\",\"value\":\"Arial\"},{\"name\":\"--bg\",\"value\":\"black\"}]:;}"` string, they are only used in the double quoted string literal to introduce `"`. — Wiktor Stribiżew, Dec 10 '18 at 16:59
@WiktorStribiżew oh yeah just now noticed those are just backslashes for string literal. i was breaking my head from last 15 minutes :p — Code Maniac, Dec 10 '18 at 17:02

score -1 · Answer 1 · answered Dec 10 '18 at 17:03

You can try this mate

Well as @wiktor mentioned there are no backslashes in your string.Those are backslashes in your string literal.in case you don't have any backslashes [\[\]] this will be enough.

Regex Pattern -> [\[\\\]]


str.gsub(/[\[\\\]]/,'')

Demo

gsub for no square brackets or backslashes

1 Answers1