Unshorten url in python 3

Question

I am using this code for unshortening urls in python 3 , but the code returns the url as it is (shortened), so what should I do to get it unshortened?

import requests
import http.client
import urllib.parse as urlparse   

def unshortenurl(url):
    parsed = urlparse.urlparse(url) 
    h = http.client.HTTPConnection(parsed.netloc) 
    h.request('HEAD', parsed.path) 
    response = h.getresponse() 
    if response.status/100 == 3 and response.getheader('Location'):
        return response.getheader('Location') 
    else: return url

you can check this https://stackoverflow.com/a/7153185/7965185 — Aybars, Dec 11 '18 at 07:50
[`if 300 <= response.status < 400`](https://stackoverflow.com/a/13628825/1270789) would be much better and clearer here! — Ken Y-N, Dec 11 '18 at 07:54

buran · Accepted Answer · 2018-12-11T07:55:41.787

1

In python3 response.status/100 == 3 would be True only for status code 300. For any other 3xx code it would be False. Use floor division instead response.status//100 == 3 or some other way to test for redirection codes.

EDIT: It looks you are using the code from SO question posted by @Aybars and there is comment at the top of the snippet what to do in python3. Also, it would have been nice to mention the source of the code.

edited Dec 11 '18 at 07:55

answered Dec 11 '18 at 07:48

buran

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Tried to change response.status/100 == 3 to response.status//100 == 3 but did not solve the problem – Youcef Dec 11 '18 at 07:55
Check the comment at the top of the code from original SO question – buran Dec 11 '18 at 07:56
Thanks for the clarification, is there a way to check if the url is shortened or not, so that I unshorten only the shortened ones in order to gain time! – Youcef Dec 11 '18 at 08:21

Unshorten url in python 3

1 Answers1