get everything in a string after a specific symbol in python using regex

Question

Hi I would like to get everything after the '_' using regex

For example: I have --> I want

'aaa_bbb_ccc' --> 'bbb_ccc'
'dd_aaaa_1' --> 'aaaa_1'
'*/_2d*_//' --> '2d*_//'

Is there anyway to do it?

Thanks in advance.

Possible duplicate of [Get a string after a specific substring](https://stackoverflow.com/questions/12572362/get-a-string-after-a-specific-substring) — Ankur Sinha, Dec 11 '18 at 13:22
Many thanks but i would like to do it using regex. I know how to do using split. — FAD, Dec 11 '18 at 13:32

score 1 · Accepted Answer · answered Dec 11 '18 at 13:23

1

I rather like the split suggestion given by @Maroun in a comment above. Here is an option using re.sub:

x = "aaa_bbb_ccc"
output = re.sub(r'^[^_]+_', '', x)
print(output)

bbb_ccc

The regex does not require much explanation, and it just removes all content up to, and including, the first underscore in the input string.

answered Dec 11 '18 at 13:23

Tim Biegeleisen

Thanks. Tbh I asked because I am trying to get better with regex but in fact i m struggling with this. – FAD Dec 11 '18 at 13:35
1

@FAD Next time you ask, make sure to include your current Python script. Had you done this, you probably would not have been downvoted. Nothing at all wrong with asking for help it you need it :-) – Tim Biegeleisen Dec 11 '18 at 13:36

1 Answers1