Python 3 remove chars from Tuples

Question

My results look like this:

('04', 3)
('06', 1) 
('07', 1) 
('09', 2)

I want them to look like this:

I've tried split (Not a string, can't do that) .replace (requires string as left operand not a tuple.) I 'think' I've tried list comprehension correctly. I'm not clear what I should actually be doing to accomplish my desired end result. I'm trying to use n00b functions since I'm learning this therefore, I'm ignore Lambda as I have no clue what that is. I am trying to stick to list, dictionary, comprehension, slice etc at this point.

My example below won't run as written, I'm just trying to show my last attempt. When I comment out lines 15, 16, 17, it runs and creates the example shown above.

fname = input("Enter file:")
if len(fname) < 1 : fname = "mbox-short.txt"
emails = open(fname)
counts=dict()
for email in emails:
    result=email.startswith('From ')
    if result is True:
        time=(email.split()[5])
        hour=(time.split(':')[0])
        counts[hour]=counts.get(hour, 0) +1
tmp=list()
for k, v in counts.items():
    tmp.append( (k, v) )
    tmp.sort()
    for char in tmp:
        if char in "(',)":
            tmp.replace(char,'')
for k in tmp:
    print (k)

how is this code related to your problem? use fixed data `mydata = [('04', 3), ('06', 1), ('07', 1), ('09', 2)]` and show what you want to do. — Patrick Artner, Dec 11 '18 at 18:18
Austin: The input is a long list of exported emails. (Class work) That was an example of the output of my script, Patrick. — Bruce, Dec 11 '18 at 18:47

score 1 · Answer 1 · answered Dec 11 '18 at 18:19

1

You can use the str.join method on a space:

for k in tmp:
    print (' '.join(k))

answered Dec 11 '18 at 18:19

blhsing

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Thank-You for your tip! – Bruce Dec 13 '18 at 20:15

score 1 · Answer 2 · answered Dec 11 '18 at 18:20

1

mydata = [('04', 3), ('06', 1), ('07', 1), ('09', 2)]

for tup in mydata:
    print(*tup)    # this uses the default sep = " " for print
                   # *tup provides each element of tup to print

Output:

See

proper name for python * operator? and
print(*objects, sep=' ', end='\n', file=sys.stdout, flush=False) to read about sep=" "

answered Dec 11 '18 at 18:20

Patrick Artner

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Thank-You for the educational links! That's a very efficient way also. – Bruce Dec 13 '18 at 20:14

score 1 · Accepted Answer · answered Dec 11 '18 at 18:21

1

Assuming [('04', 3), ('06', 1), ('07', 1), ('09', 2)] is your input, you could just do:

tupls = [('04', 3), ('06', 1), ('07', 1), ('09', 2)]

for x, y in tupls:
    print(x, y)

# 04 3
# 06 1
# 07 1
# 09 2

answered Dec 11 '18 at 18:21

Austin

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Thanks Austin. I feel like a moron after seeing your answer. it worked perfectly. I have no idea why i didn't get that. Thank-You. -= Bruce – Bruce Dec 11 '18 at 18:50

score 1 · Answer 4 · answered Dec 11 '18 at 18:27

1

This may help you

# ....
# Rest of your code
# ....
tmp=list()
for k, v in counts.items():
    tmp.append( (int(k), int(v)) ) # !!! make it integer
    tmp.sort()

for k in tmp:
    print (k)

answered Dec 11 '18 at 18:27

ozcanyarimdunya

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Thank-You for your example! – Bruce Dec 13 '18 at 20:15

Python 3 remove chars from Tuples

4 Answers4