Regex extract string based on pattern

Question

See below string we have in document

    32Main Section
    32.1Assignment and transfers by Obligors
    32.2Additional Borrowers
    (a)Subject to compliance with the provisions of paragraphs (c) and (d) of Clause 28.10 ("Know your customer" checks),

Output Expected (List string only if they have this xx.xx pattern at the start of the line)

32.1Assignment and transfers by Obligors
32.2Additional Borrowers

Regex we are trying \d+(\.\d{1,2}.*)

But this gives us 3rd line also which we dont have as it has number in the middle of line. We want to list only lines which start with the number or decimal...

@WiktorStribiżew - how to modify this further that at start it could be number or decimal (so it could be 10 or 10.2 and after that is text) — user3657339, Dec 12 '18 at 12:18
@WiktorStribiżew - can you add this as answer pls - ^\d+(?:\.\d{1,2})?.* - this worked for me — user3657339, Dec 12 '18 at 12:22
It occurs to me that it might not be really a good solution. The `(?:\.\d{1,2})?` is an optional pattern, and since you are using `.*` after it, it means you do not even need that one. Just `^\d.*` will do then. Else, you need to specify a delimiter for the number. Say, `^\d+(?:\.\d{1,2})?[ .].*` — Wiktor Stribiżew, Dec 12 '18 at 12:23
@WiktorStribiżew `^\d.*` this is really neat. cheers mate :) — Code Maniac, Dec 12 '18 at 12:25
@WiktorStribiżew but it will than match `23.abc` and also `32Main` . is it desirable op ? — Code Maniac, Dec 12 '18 at 12:26

score 0 · Answer 1 · answered Dec 12 '18 at 12:18

0

You can try this mate

^\d+\.\d+.*

Explanation

^ - Anchor to start of string.
\d+\.\d+ - Matches xx.xx pattern (x is number).
.* - Matches anything except newline. zero or more time (greedy mode)

Demo

answered Dec 12 '18 at 12:18

Code Maniac

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score 0 · Accepted Answer · answered Dec 12 '18 at 12:33

0

You want to match any string starting with a digit, so ^\d+(?:\.\d{1,2})?.* that can be shortened to ^\d.* will do the job.

A better idea is to specify a delimiter for the number. Say,

^\d+(?:\.\d{1,2})?[ .].*
                  ^^^^

Or make sure there is no digit:

^\d+(?:\.\d{1,2})?(?!\d).*
                  ^^^^^^

The [ .] will require a space or . after the initial number.

Details

^ - start of a string
\d+ - 1+ digits
(?:\.\d{1,2})? - an optional non-capturing group
- \. - a dot
- \d{1,2} - 1 or 2 digits
[ .] - a space or .
.* - the rest of the string.

answered Dec 12 '18 at 12:33

Wiktor Stribiżew

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is it possible to add space between number and when words start... like "43.1 Agreement" using REGEX – user3657339 Dec 12 '18 at 12:46
@user3657339 Yes, `Regex.Replace(s, @"^(\d+(?:\.\d{1,2})?)(?![\d\s])(.*)", "$1 $2")` – Wiktor Stribiżew Dec 12 '18 at 12:49
@user3657339 Glad it worked for you. Please also consider upvoting if my answer proved helpful to you. – Wiktor Stribiżew Dec 13 '18 at 06:03

Regex extract string based on pattern

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