Can I print both array index and value in the same line?

Question

#!/bin/sh
IFS=$'\n' ARR=(`lvs | grep -v LV | awk '{print $1}'`)

for A in ${ARR[*]}
do
        echo $A
done

for ((i=0;i<${#ARR[*]};i++))
do
        echo $i
done

The result of the above script

home

root

swap

fedora

0

1

2

3

I want the following results

0 home

1 root

2 swap

3 fedora

`for idx in "${!ARR[@]}"; do item=${ARR[$idx]}; echo "$idx $item" done` — Charles Duffy, Dec 13 '18 at 05:28
BTW, arrays aren't guaranteed to work with `#!/bin/sh`; on many systems, `/bin/sh` is provided by dash, which doesn't support them. Always use `#!/bin/bash` if you want to use bash-only features. — Charles Duffy, Dec 13 '18 at 05:30

score 0 · Accepted Answer · answered Dec 13 '18 at 02:33

0

I suggest that you concatenate each $A with a separator, and then echo the string at the end if you want it on one line.

answered Dec 13 '18 at 02:33

Sweet Chilly Philly

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sorry, It is not the answer I want. – sangyul lee Dec 13 '18 at 04:14

Can I print both array index and value in the same line?

1 Answers1