call_user_func_array("shell_exec", ...) not working in php

Question

In php, when I call

shell_exec('ls');

it executes the commands 'ls' in shell and returns a string which consists of set of files in the directory

But when I call

 call_user_func_array('shell_exec', 'ls');

it is always returning false. What mistake am I doing?

The second argument to `call_user_func_array` is supposed to be an array. — Barmar, Dec 13 '18 at 03:27

score 0 · Accepted Answer · answered Dec 13 '18 at 03:27

0

Second parameter to the function call_user_func_array() should be an array.

<?php
    if(call_user_func_array("shell_exec", array("ls")))
        echo "TRUE";
    else
        echo "FALSE";

works as expected.

answered Dec 13 '18 at 03:27

Romeo Sierra

1 Answers1