Let's assume that I have the following data-frame:
df_raw = pd.DataFrame({"id": [102, 102, 103, 103, 103], "val1": [9,2,4,7,6], "val2": [np.nan, 3, np.nan, 4, 5], "val3": [4, np.nan, np.nan, 5, 1], "date": [pd.Timestamp(2002, 1, 1), pd.Timestamp(2002, 3, 3), pd.Timestamp(2003, 4, 4), pd.Timestamp(2003, 8, 9), pd.Timestamp(2005, 2, 3)]})
I want to have access to the rows where the first occurrence of each id
is. So these rows would be:
df_first = pd.DataFrame({"id": [102, 103], "val1": [9, 4], "val2": [np.nan, np.nan], "val3": [4, np.nan], "date": [pd.Timestamp(2002, 1, 1), pd.Timestamp(2003, 4, 4)]})
Basically, at the end what I would like to achieve is fill up the NaN
s that appear in the first occurrence of each id
. So the final data frame might be:
df_processed = pd.DataFrame({"id": [102, 102, 103, 103, 103], "val1": [9,2,4,7,6], "val2": [-1, 3, -1, 4, 5], "val3": [4, np.nan, -1, 5, 1], "date": [pd.Timestamp(2002, 1, 1), pd.Timestamp(2002, 3, 3), pd.Timestamp(2003, 4, 4), pd.Timestamp(2003, 8, 9), pd.Timestamp(2005, 2, 3)]})
An important note is that the rows are already grouped by id and date and sorted in a ascending manner. So they appear exactly as in the provided example.