Get the square root of an integer in Haskell

Question

I have a simple function, which is to get the hypotenuse of a pythagorean triangle, but for the type of Int.

Here is my code:

hypotenuse :: Int -> Int -> Int
hypotenuse a b = sqrt(a*a + b*b)

I need to round up the result.

For example: hypotenuse 500 0 --result:500 :: Int hypotenuse 500 30 --result:501 :: Int

@FrownyFrog That should have been an answer. Either way, the question has been asked already. — Zeta, Dec 15 '18 at 18:36

score 2 · Accepted Answer · answered Dec 15 '18 at 18:34

Without outright stating the solution, here are some functions you may find handy:

The details of your hypotenuse function are up to you, so I will leave the implementation to your discretion.

1 Answers1