Python, Putting x = 0 into a '' bracket

Question

Not sure if the tittle is 100% correct, please correct me if im wrong

I have a small python script as follows

x = 0 #counter


with open('products(x).csv', 'w') as csvfile:

I'm trying to make it output

product0.csv

I have a loop set up the increases the value of x

x += 1

So what I'm hoping is it will create product0.csv product1.csv product2.csv

Etc, etc.

I have tried

with open('products'(x)'.csv', 'w') as csvfile:

And I just recieve an error

  File "web.py", line 30
    with open('products'(x)'.csv', 'w') as csvfile:
                                ^

products is just the first part of the name of the csv file i want to output. its nothing related to my python code. — Mic, Dec 19 '18 at 07:11

nishant · Answer 1 · 2018-12-19T07:14:02.560

2

Use this

with open('products('+str(x)+').csv', 'w') as csvfile:

edited Dec 19 '18 at 07:14

answered Dec 19 '18 at 07:11

nishant

Im getting this error File "web.py", line 30, in with open('product_scrapped/products('+x+').csv', 'w') as csvfile: TypeError: can only concatenate str (not "int") to str – Mic Dec 19 '18 at 07:13
@Mic updated use it – nishant Dec 19 '18 at 07:14

score 2 · Answer 2 · answered Dec 19 '18 at 07:11

2

with open('products({}).csv'.format(x), 'w') as csvfile:
        ...

answered Dec 19 '18 at 07:11

P.hunter

score 1 · Answer 3 · answered Dec 19 '18 at 07:11

1

String formatting should do the trick:

x = 0
filename = 'product{}.csv'.format(x)

answered Dec 19 '18 at 07:11

Mureinik

score 1 · Answer 4 · answered Dec 19 '18 at 07:13

Try

x = 0 #counter        
with open('products'+str(x)+'.csv', 'w') as csvfile:

instead of

x = 0 #counter        
with open('products(x).csv', 'w') as csvfile:

because x is an integer. You first need to convert it to string with str() and then concatenate using the + operator.

Another way is to use format() as in

with open('products{}.csv'.format(x), 'w')

4 Answers4